forked from ignacio-chiazzo/Algorithms-Leetcode-Javascript
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathMinimize_Maximum_Pair_Sum_In_Array.js
46 lines (34 loc) · 1.26 KB
/
Minimize_Maximum_Pair_Sum_In_Array.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
/*
Minimize Maximum Pair Sum in Array
https://leetcode.com/problems/minimize-maximum-pair-sum-in-array/description/
The pair sum of a pair (a,b) is equal to a + b. The maximum pair sum is the largest pair sum in a list of pairs.
For example, if we have pairs (1,5), (2,3), and (4,4), the maximum pair sum would be max(1+5, 2+3, 4+4) = max(6, 5, 8) = 8.
Given an array nums of even length n, pair up the elements of nums into n / 2 pairs such that:
Each element of nums is in exactly one pair, and
The maximum pair sum is minimized.
Return the minimized maximum pair sum after optimally pairing up the elements.
Example 1:
Input: nums = [3,5,2,3]
Output: 7
Explanation: The elements can be paired up into pairs (3,3) and (5,2).
The maximum pair sum is max(3+3, 5+2) = max(6, 7) = 7.
Example 2:
Input: nums = [3,5,4,2,4,6]
Output: 8
Explanation: The elements can be paired up into pairs (3,5), (4,4), and (6,2).
The maximum pair sum is max(3+5, 4+4, 6+2) = max(8, 8, 8) = 8.
*/
/**
* @param {number[]} nums
* @return {number}
*/
var minPairSum = function(nums) {
nums.sort((a, b) => a-b);
let i = 0, j = nums.length - 1;
let max = -Infinity;
while (i < j) {
max = Math.max(max, nums[i++] + nums[j--]);
}
return max;
};
module.exports.minPairSum = minPairSum;