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1174-immediate-food-delivery-ii.sql
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-- 1174. Immediate Food Delivery II
-- Medium
-- https://leetcode.com/problems/immediate-food-delivery-ii
/*
Table: Delivery
+-----------------------------+---------+
| Column Name | Type |
+-----------------------------+---------+
| delivery_id | int |
| customer_id | int |
| order_date | date |
| customer_pref_delivery_date | date |
+-----------------------------+---------+
delivery_id is the primary key of this table.
The table holds information about food delivery to customers that make orders at some date and specify a preferred delivery date (on the same order date or after it).
If the customer's preferred delivery date is the same as the order date, then the order is called immediate; otherwise, it is called scheduled.
The first order of a customer is the order with the earliest order date that the customer made. It is guaranteed that a customer has precisely one first order.
Write an SQL query to find the percentage of immediate orders in the first orders of all customers, rounded to 2 decimal places.
The query result format is in the following example.
Example 1:
Input:
Delivery table:
+-------------+-------------+------------+-----------------------------+
| delivery_id | customer_id | order_date | customer_pref_delivery_date |
+-------------+-------------+------------+-----------------------------+
| 1 | 1 | 2019-08-01 | 2019-08-02 |
| 2 | 2 | 2019-08-02 | 2019-08-02 |
| 3 | 1 | 2019-08-11 | 2019-08-12 |
| 4 | 3 | 2019-08-24 | 2019-08-24 |
| 5 | 3 | 2019-08-21 | 2019-08-22 |
| 6 | 2 | 2019-08-11 | 2019-08-13 |
| 7 | 4 | 2019-08-09 | 2019-08-09 |
+-------------+-------------+------------+-----------------------------+
Output:
+----------------------+
| immediate_percentage |
+----------------------+
| 50.00 |
+----------------------+
Explanation:
The customer id 1 has a first order with delivery id 1 and it is scheduled.
The customer id 2 has a first order with delivery id 2 and it is immediate.
The customer id 3 has a first order with delivery id 5 and it is scheduled.
The customer id 4 has a first order with delivery id 7 and it is immediate.
Hence, half the customers have immediate first orders.
*/
SELECT
ROUND(100 * SUM(
CASE
WHEN order_date = customer_pref_delivery_date THEN 1
ELSE 0
END
) / COUNT(*), 2) AS immediate_percentage
FROM
(
SELECT
customer_id,
MIN(order_date) AS order_date,
MIN(customer_pref_delivery_date) AS customer_pref_delivery_date
FROM
Delivery
GROUP BY
customer_id
) AS first_order;