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Online Election.py
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'''
In an election, the i-th vote was cast for persons[i] at time times[i].
Now, we would like to implement the following query function: TopVotedCandidate.q(int t) will return the number of the person that was leading the election at time t.
Votes cast at time t will count towards our query. In the case of a tie, the most recent vote (among tied candidates) wins.
Example 1:
Input: ["TopVotedCandidate","q","q","q","q","q","q"], [[[0,1,1,0,0,1,0],[0,5,10,15,20,25,30]],[3],[12],[25],[15],[24],[8]]
Output: [null,0,1,1,0,0,1]
Explanation:
At time 3, the votes are [0], and 0 is leading.
At time 12, the votes are [0,1,1], and 1 is leading.
At time 25, the votes are [0,1,1,0,0,1], and 1 is leading (as ties go to the most recent vote.)
This continues for 3 more queries at time 15, 24, and 8.
Note:
1 <= persons.length = times.length <= 5000
0 <= persons[i] <= persons.length
times is a strictly increasing array with all elements in [0, 10^9].
TopVotedCandidate.q is called at most 10000 times per test case.
TopVotedCandidate.q(int t) is always called with t >= times[0].
'''
class TopVotedCandidate(object):
def __init__(self, persons, times):
"""
:type persons: List[int]
:type times: List[int]
"""
person_vote = {}
current_person = None
self.persons = []
for p in persons:
if p in person_vote:
person_vote[p] += 1
else:
person_vote[p] = 1
if current_person is None or person_vote[current_person] <= person_vote[p]:
current_person = p
self.persons.append(current_person)
self.times = times
def q(self, t):
"""
:type t: int
:rtype: int
"""
left = 0
right = len(self.persons) - 1
while left < right:
mid = (left + right + 1) // 2
if self.times[mid] == t:
return self.persons[mid]
elif self.times[mid] < t:
left = mid
else:
right = mid - 1
if self.times[right] <= t:
return self.persons[right]
return self.persons[left]
# Your TopVotedCandidate object will be instantiated and called as such:
# obj = TopVotedCandidate(persons, times)
# param_1 = obj.q(t)