Long version of Recusion for tower of Hanoi.py

# Learn Recursion by Solving the Tower of Hanoi Puzzle

# First solution this seems conuluted and I hope the second solution is much better

NUMBER_OF_DISKS = 4
number_of_moves = 2**NUMBER_OF_DISKS - 1
rods = {"A": list(range(NUMBER_OF_DISKS, 0, -1)), "B": [], "C": []}


def make_allowed_move(rod1, rod2):
    forward = False
    if not rods[rod2]:
        forward = True
    elif rods[rod1] and rods[rod1][-1] < rods[rod2][-1]:
        forward = True
    if forward:
        print(f"Moving disk {rods[rod1][-1]} from {rod1} to {rod2}")
        rods[rod2].append(rods[rod1].pop())
    else:
        print(f"Moving disk {rods[rod2][-1]} from {rod2} to {rod1}")
        rods[rod1].append(rods[rod2].pop())

    # display our progress
    print(rods, "\n")


def move(n, source, auxiliary, target):
    # display starting configuration
    print(rods, "\n")
    for i in range(number_of_moves):
        remainder = (i + 1) % 3
        if remainder == 1:
            if n % 2 != 0:
                print(f"Move {i + 1} allowed between {source} and {target}")
                make_allowed_move(source, target)
            else:
                print(f"Move {i + 1} allowed between {source} and {auxiliary}")
                make_allowed_move(source, auxiliary)
        elif remainder == 2:
            if n % 2 != 0:
                print(f"Move {i + 1} allowed between {source} and {auxiliary}")
                make_allowed_move(source, auxiliary)
            else:
                print(f"Move {i + 1} allowed between {source} and {target}")
                make_allowed_move(source, target)
        elif remainder == 0:
            print(f"Move {i + 1} allowed between {auxiliary} and {target}")
            make_allowed_move(auxiliary, target)


# initiate call from source A to target C with auxiliary B
move(NUMBER_OF_DISKS, "A", "B", "C")