QtJambi Widget moves without borders

[ITSweets]

Hi, long time no see. Recently I've been trying to dynamically load.ui files using QtJambi's traditional Widget style. This is all very well. I want to set the borderless movement of this form. So I rewrote the eventFilter method. Because no border requires mouse event related operations. The result is the following code.

@Override
public boolean eventFilter(QObject watched, QEvent event)
{
    if (watched.equals(this))
    {
        try
        {
            QMouseEvent mouseEvent = (QMouseEvent) event;
            
            if (mouseEvent.type().equals(QEvent.Type.MouseButtonPress))
            {
                if (mouseEvent.button().equals(Qt.MouseButton.LeftButton) && mouseEvent.pos().y() <= 26)
                {
                    mousePressed = true;
                    mousePoint.setX(mouseEvent.globalPos().x() - pos().x());
                    mousePoint.setY(mouseEvent.globalPos().y() - pos().y());
                }
            } else if (mouseEvent.type().equals(QEvent.Type.MouseButtonRelease))
            {
                mousePressed = false;
            } else if (mouseEvent.type().equals(QEvent.Type.MouseMove))
            {
                if (mousePressed)
                {
                    move(mouseEvent.globalPos().x() - mousePoint.x(), mouseEvent.globalPos().y() - mousePoint.y());
                    return true;
                }
            }
        } catch (Exception e)
        {
            e.printStackTrace();
        }
    }

    return super.eventFilter(watched, event);
}

This code implements borderless movement, but I think the way it does it is a little unsatisfying. When forced to convert an event to a QMouseEvent. If the event is not related to the QMouseEvent. Casting throws an exception. To do this I used a try catch surround to solve this problem. In C++ I can use static_cast to convert the event type. But in Java it seems like you can only cast, and that's the problem. Is there a more elegant way?

[omix]

In Java, you check an object's classtype with instanceof:

if(mouseEvent instanceof QMouseEvent){
    QMouseEvent mouseEvent = (QMouseEvent) event;
}

QMouseEvent is only used for certain event types (QEvent.type()). The following is save:

switch(mouseEvent.type()){
case MouseButtonPress:
case MouseButtonRelease:
case MouseMove:
    QMouseEvent mouseEvent = (QMouseEvent) event;
break;
default: break;
}

I suggest to use == instead of equals in case of QObjects (or other pointer-based types):

if (this==watched){
}

I also wonder if your code isn't actually better placed in the object's event method.