Create Count of Smaller Numbers After Self

Author: Piyush6869

LeetcodeProblems/Algorithms/Count of Smaller Numbers After Self

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+def countSmaller(nums):
+    result = []
+    for i in range(len(nums)):
+        count = 0
+        for j in range(i + 1, len(nums)):
+            if nums[j] < nums[i]:
+                count += 1
+        result.append(count)
+    return result