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Counter组件设定最小值为1时,输入0,数字溢出bind:linout不会被触发 #1501

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sizeoflove1 opened this issue Mar 15, 2022 · 1 comment
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Bug 该 Issue 提出了一个 Bug 已解决:+1: Issue 已解决

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@sizeoflove1
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设备型号:
iPhone12

LinUI 版本:
0.9.7

微信小程序基础库版本:
2.22.1

微信开发者工具版本:
1.06.2111300

问题描述及重现步骤:
Counter组件通过设定min属性、设定最小值为1时,输入0(input方式,不是icon),数字溢出bind:linout不会被触发。

现在的behavior是:输入0,bind:linout不被触发,但是0也没有被accept,count的数字是上一个有效数字。比如上一个数字是99,输入0后,count还是99,linout不被触发。

期望的hehavior是:输入0,linout被触发,count自动变为设定的最小值1.

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@sizeoflove1 sizeoflove1 added the Bug 该 Issue 提出了一个 Bug label Mar 15, 2022
@smileShirmy
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smileShirmy commented May 15, 2022

感谢反馈,问题已修复,将在下个版本中推出

@smileShirmy smileShirmy added the 已解决:+1: Issue 已解决 label May 15, 2022
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