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a Expr like col(a) > utf('8'). We shouldn't cast col(a).
col(a) > utf('8')
col(a)
#[test] fn between_infer_cheap_type() -> Result<()> { let expr = Expr::Between(Between::new( Box::new(col("a")), false, // (cast('2002-05-08' as date) + interval '1 months') Box::new(Expr::BinaryExpr(BinaryExpr { left: Box::new(Expr::Cast(Cast { expr: Box::new(Expr::Literal(Utf8(Some("2002-05-08".to_string())))), data_type: DataType::Date32, })), op: Operator::Plus, right: Box::new(Expr::Literal(ScalarValue::IntervalYearMonth(Some(1)))), })), Box::new(Expr::Literal(Utf8(Some("2002-12-08".to_string())))), )); let empty = empty_with_type(DataType::Utf8); let plan = LogicalPlan::Filter(Filter::try_new(expr, empty)?); // TODO let expected = "Filter: CAST(a AS Date32) BETWEEN CAST(Utf8(\"2002-05-08\") AS Date32) + IntervalYearMonth(\"1\") AND CAST(Utf8(\"2002-12-08\") AS Date32)\ \n EmptyRelation"; assert_analyzed_plan_eq(Arc::new(TypeCoercion::new()), &plan, expected) }
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Describe the bug
a Expr like
col(a) > utf('8')
.We shouldn't cast
col(a)
.To Reproduce
Expected behavior
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Additional context
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The text was updated successfully, but these errors were encountered: