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5VDC vs. 3.3VDC for IR LED circuit #9
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If you could put in an extra led, so you have 8 in total, then put 2 in series with a resistor, multiply with 4. Will also lower the current through the FET. As you will only have 4 x 100mA current draw through the FET |
Good idea Thomas. What if I used 3-pair plus one single? I would still have 4x100mA current draw through the FET and I think I would only need to use slightly different current limiting resistors for the 1 vs. pairs to do it. In fact, the IR LED FV is 1.4-1.8 at 100mA so I would only need to offset from 3.3 down to 2.8-3.6 so maybe I wouldn't even need a current limiting resistor for the pairs. Do you see any significant issues with that approach? The IR design uses an odd number of LEDs so that one of them is completely forward-facing at a 0-degree angle for maximum range. Another advantage for using 3.3VDC for the IR LED circuit is that if there are two LDOs, one won't need to dissipate a larger voltage differential between the power supply and the 3.3VDC LDO and users would be able to use a more common 5VDC power supply. Taking it a step further would be to consolidate to a single LDO (the AMS1117 can push 1A) with additional capacitance to compensate and push all components to the top-side while still keeping the board under 5x5cm... Good idea/bad idea? |
Hmm of course you could just have 7 leds, with a larger resistor for the Could probably also go with a single ldo. But definitely need good |
Interesting test of the IR LEDs.
Far cry from the data sheet. So pairing is a good idea unless we use a heavy duty FET 😉I should try a few to see the variance between individual LEDs. This means that I we will need current limiting resistors because the IR LEDs will pull whatever is available above 1.25VDC / 100mA and strain the FET. |
The v0.5 version of the IR LED circuit was 5V requiring 35 ohm 0.35watt current limiting resistors and was laid out using 0603 resistor footprints. During part selection, I found that it was nearly impossible to find a resistor that could meet the power requirements so for the dev board, I reverted to driving the IR LEDs with 3.3v allowing the use of a 15 ohm 0.18 watt resistor in the 0603 package.
The open issue is which voltage should be used for the final board. If 5VDC, then at a minimum, we need to change the resistor footprint to 0805.
/cc @tbowmo @fallberg
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