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q63_unique_paths_ii.rs
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/**
* 63. Unique Paths II
* https://leetcode.com/problems/unique-paths-ii/
*
* A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
*
* The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
*
* Now consider if some obstacles are added to the grids. How many unique paths would there be?
*
*
*
* An obstacle and empty space is marked as 1 and 0 respectively in the grid.
*
* Note: m and n will be at most 100.
*
* Example 1:
*
* Input:
* [
* [0,0,0],
* [0,1,0],
* [0,0,0]
* ]
* Output: 2
* Explanation:
* There is one obstacle in the middle of the 3x3 grid above.
* There are two ways to reach the bottom-right corner:
* 1. Right -> Right -> Down -> Down
* 2. Down -> Down -> Right -> Right
*/
fn unique_paths_with_obstacles(mut obstacle_grid: Vec<Vec<i32>>) -> i32 {
if obstacle_grid.is_empty() || obstacle_grid[0].is_empty() {
return 0;
}
let (row, column) = (obstacle_grid[0].len(), obstacle_grid.len());
for y in 0..column {
for x in 0..row {
if x == 0 && y == 0 {
obstacle_grid[y][x] = 1 - obstacle_grid[y][x];
} else if obstacle_grid[y][x] == 1 {
obstacle_grid[y][x] = 0; // if the current grid is invalid, it should be set to 0
} else {
if x != 0 {
// "x != 0" means you can add the value from left
obstacle_grid[y][x] += obstacle_grid[y][x - 1];
}
if y != 0 {
// "y != 0" means you can add the value from up
obstacle_grid[y][x] += obstacle_grid[y - 1][x];
}
}
}
}
obstacle_grid[column - 1][row - 1]
}
#[test]
fn q63_test() {
assert_eq!(
unique_paths_with_obstacles(vec![vec![0, 0, 0], vec![0, 1, 0], vec![0, 0, 0]]),
2
);
assert_eq!(
unique_paths_with_obstacles(vec![vec![0, 1, 0], vec![0, 1, 0], vec![0, 0, 0]]),
1
);
assert_eq!(
unique_paths_with_obstacles(vec![vec![0, 1, 0], vec![0, 0, 0], vec![0, 0, 0]]),
3
);
assert_eq!(
unique_paths_with_obstacles(vec![vec![0], vec![0], vec![0]]),
1
);
}