输入一棵二叉搜索树,将该二叉搜索树转换成一个排序的双向链表。要求不能创建任何新的结点,只能调整树中结点指针的指向。
#include <iostream>
#include "tree_util.h"
using namespace std;
class Solution {
public:
TreeNode* Convert(TreeNode* pRootOfTree) {
if (!pRootOfTree) {
return NULL;
}
TreeNode *prev_last = NULL;
convert_core(pRootOfTree, prev_last);
while (prev_last->left) {
prev_last = prev_last->left;
}
return prev_last;
}
private:
static void convert_core(TreeNode *node, TreeNode *&prev_last) {
if (node->left) {
convert_core(node->left, prev_last);
}
if (prev_last) {
prev_last->right = node;
}
node->left = prev_last;
prev_last = node;
if (node->right) {
convert_core(node->right, prev_last);
}
}
};
int main(int argc, char *argv[])
{
{
int arr[] = { 10, 6, 4, -1, -1, 8, -1, -1, 14, 12, -1, -1, 16, -1, -1 };
TreeNode* root = create_pre_order(arr, NELEM(arr));
pre_order(root);
TreeNode *p = Solution().Convert(root), *q;
while (p) {
q = p->right;
cout << p->val << " ";
delete p;
p = q;
}
cout << endl;
// delete_postorder(root);
}
{
int arr[] = { 10, 9, 8, -1, -1, -1, -1 };
TreeNode* root = create_pre_order(arr, NELEM(arr));
pre_order(root);
TreeNode *p = Solution().Convert(root), *q;
while (p) {
q = p->right;
cout << p->val << " ";
delete p;
p = q;
}
cout << endl;
// delete_postorder(root);
}
{
int arr[] = { 10, -1, 11, -1, 12, -1, -1 };
TreeNode* root = create_pre_order(arr, NELEM(arr));
pre_order(root);
TreeNode *p = Solution().Convert(root), *q;
while (p) {
q = p->right;
cout << p->val << " ";
delete p;
p = q;
}
cout << endl;
// delete_postorder(root);
}
return 0;
}
输出结果:
walk with stack:
10 6 4 8 14 12 16
4 6 8 10 12 14 16
walk with stack:
10 9 8
8 9 10
walk with stack:
10 11 12
10 11 12