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_408.java
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package com.fishercoder.solutions.firstthousand;
public class _408 {
public static class Solution1 {
public boolean validWordAbbreviation(String word, String abbr) {
if (abbr.length() > word.length()) {
return false;
} else {
char[] abbrChars = abbr.toCharArray();
char[] wordChars = word.toCharArray();
if (abbr.length() == word.length()) {
boolean prevDigit = false;
for (int i = 0, j = 0; i < abbrChars.length && j < wordChars.length; i++, j++) {
if (Character.isDigit(abbrChars[i]) && !prevDigit) {
prevDigit = true;
if (Character.getNumericValue(abbrChars[i]) != 1) {
return false;
}
} else if (Character.isDigit(abbrChars[i]) && prevDigit) {
return false;
} else if (abbrChars[i] != wordChars[j]) {
return false;
} else if (prevDigit) {
prevDigit = false;
}
}
return true;
} else {
StringBuilder stringBuilder = new StringBuilder();
boolean firstDigit = true;
for (int i = 0, j = 0; i < abbrChars.length && j < wordChars.length; i++) {
while (i < abbrChars.length && Character.isDigit(abbrChars[i])) {
if (firstDigit && Character.getNumericValue(abbrChars[i]) == 0) {
return false;
}
stringBuilder.append(abbrChars[i]);
i++;
firstDigit = false;
}
firstDigit = true;
if (!stringBuilder.toString().isEmpty()) {
int number = Integer.valueOf(stringBuilder.toString());
j += number;
stringBuilder.setLength(0);
}
if ((i >= abbrChars.length && j < wordChars.length)
|| (i < abbrChars.length && j >= wordChars.length)) {
return false;
}
if (i < abbrChars.length
&& j < wordChars.length
&& abbrChars[i] != wordChars[j]) {
return false;
}
if (j > wordChars.length && i <= abbrChars.length) {
return false;
}
j++;
}
return true;
}
}
}
}
public static class Solution2 {
public boolean validWordAbbreviation(String word, String abbr) {
int aLen = abbr.length();
int wLen = word.length();
if (aLen > wLen) {
return false;
}
int i = 0;
int j = 0;
while (i < wLen && j < aLen) {
if (word.charAt(i) == abbr.charAt(j)) {
i++;
j++;
continue;
}
// now the two chars don't match, then the char in abbr should be a valid digit: 0 <
// x <= 9
if (abbr.charAt(j) == '0' || !Character.isDigit(abbr.charAt(j))) {
return false;
}
// now we count the number of letters that are abbreviated, i.e. get the number from
// abbr before next letter shows up in abbr
int num = 0;
while (j < aLen && Character.isDigit(abbr.charAt(j))) {
num = num * 10 + (abbr.charAt(j) - '0');
j++;
}
i += num;
}
return i == wLen && j == aLen;
}
}
}