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14.1.8 节 #63

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johnny880730 opened this issue Feb 15, 2023 · 0 comments

johnny880730 commented Feb 15, 2023 •

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实际描述

原文页码：288
原文段落：A.ref1 = nil: 移除灰色对象 A 对白色对象 B 的引用（ref2）；

A.ref1 = nil: 移除灰色对象 A 对白色对象 B 的引用 （ref2）；

预期描述

根据第389页顶部的图 14-5 来看，A.ref1 = B，所以原句里括号的部分是 ref1 吧

A.ref1 = nil: 移除灰色对象 A 对白色对象 B 的引用 （ref1）；

附图

必要时，请附上相关页面的照片或者截图

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