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Constructs a type by extracting from Type all union members that are assignable to Union.
type T0 = Extract<"a" | "b" | "c", "a" | "f">; // type T0 = "a" type T1 = Extract<string | number | (() => void), Function>; // type T1 = () => void
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/** * Extract from T those types that are assignable to U */ type Extract<T, U> = T extends U ? T : never;
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Constructs a type by extracting from Type all union members that are assignable to Union.
The text was updated successfully, but these errors were encountered: