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smaple 除了订阅源obs以外,还可以监视另外一个notifier 之间有源就取最新的源发送 两次noti之间如果没有源的话,就不会发送
smaple
noti
func sample(){ let disbag = DisposeBag() let source1 = PublishSubject<Int>() let noti1 = PublishSubject<String>() source1.sample(noti1) .subscribe(onNext: { print($0) },onCompleted: { print("1===completed") }).disposed(by: disbag) source1.onNext(1) //1 noti1.onNext("A") source1.onNext(2) //2 noti1.onNext("B") noti1.onNext("C") source1.onNext(3) source1.onNext(4) noti1.onNext("D") source1.onNext(5) noti1.onCompleted() /* 1 2 4 5 */ }
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smaple
除了订阅源obs以外,还可以监视另外一个notifier之间有源就取最新的源发送
两次
noti
之间如果没有源的话,就不会发送The text was updated successfully, but these errors were encountered: