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第29题(2019-08-29):什么是防抖和节流?有什么区别?如何实现? #31

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qappleh opened this issue Aug 29, 2019 · 1 comment
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@qappleh
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qappleh commented Aug 29, 2019

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qappleh commented Aug 30, 2019

1.防抖
触发高频事件后n秒内函数只会执行一次,如果n秒内高频事件再次被触发,则重新计算时间

思路:
每次触发事件时都取消之前的延时调用方法

function debounce(fn) {
      let timeout = null; // 创建一个标记用来存放定时器的返回值
      return function () {
        clearTimeout(timeout); // 每当用户输入的时候把前一个 setTimeout clear 掉
        timeout = setTimeout(() => { // 然后又创建一个新的 setTimeout, 这样就能保证输入字符后的 interval 间隔内如果还有字符输入的话,就不会执行 fn 函数
          fn.apply(this, arguments);
        }, 500);
      };
    }
    function sayHi() {
      console.log('防抖成功');
    }

    var inp = document.getElementById('inp');
    inp.addEventListener('input', debounce(sayHi)); // 防抖  

2.节流
高频事件触发,但在n秒内只会执行一次,所以节流会稀释函数的执行频率

思路:
每次触发事件时都判断当前是否有等待执行的延时函数

function throttle(fn) {
      let canRun = true; // 通过闭包保存一个标记
      return function () {
        if (!canRun) return; // 在函数开头判断标记是否为true,不为true则return
        canRun = false; // 立即设置为false
        setTimeout(() => { // 将外部传入的函数的执行放在setTimeout中
          fn.apply(this, arguments);
          // 最后在setTimeout执行完毕后再把标记设置为true(关键)表示可以执行下一次循环了。当定时器没有执行的时候标记永远是false,在开头被return掉
          canRun = true;
        }, 500);
      };
    }
    function sayHi(e) {
      console.log(e.target.innerWidth, e.target.innerHeight);
    }
    window.addEventListener('resize', throttle(sayHi));  

@qappleh qappleh added the js label Nov 27, 2019
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