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You are given an array (which will have a length of at least 3, but could be very large) containing integers.
The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer N.
Write a method that takes the array as an argument and returns this "outlier" N.

Examples
[2, 4, 0, 100, 4, 11, 2602, 36]
Should return: 11 (the only odd number)

[160, 3, 1719, 19, 11, 13, -21]
Should return: 160 (the only even number)



def find_outlier(integers):
  return #TODO


test.assert_equals(find_outlier([2, 4, 6, 8, 10, 3]), 3)
test.assert_equals(find_outlier([2, 4, 0, 100, 4, 11, 2602, 36]), 11)
test.assert_equals(find_outlier([160, 3, 1719, 19, 11, 13, -21]), 160)




















































#my_solution
def find_outlier(integers):
    odd = 0
    even = 0
    for i in integers:
        if (i % 2) == 0:
            odd += 1
        else:
            even += 1
    if odd == 1:
        #array is even, outlier is odd
        for i in integers:
            if (i % 2) == 0:
                return i #return outlier as odd
    if even == 1:
        #array is odd, outlier is even
        for i in integers:
            if (i % 2) == 1:
                return i # return outlier as even