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You are given two strings order and s. All the characters of order are unique and were sorted in some custom order previously.
Permute the characters of s so that they match the order that order was sorted. More specifically, if a character x occurs before a character y in order, then x should occur before y in the permuted string.
Return any permutation of s that satisfies this property.
*/
class Solution {
public:
string customSortString(string S, string T) {
sort(T.begin(), T.end(),
[&](char a, char b) { return S.find(a) < S.find(b); });