-
Notifications
You must be signed in to change notification settings - Fork 24
/
Copy path1380-lucky-numbers-in-a-matrix.js
63 lines (54 loc) · 1.62 KB
/
1380-lucky-numbers-in-a-matrix.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
// 1380. Lucky Numbers in a Matrix
// Easy 72%
// Given a m * n matrix of distinct numbers, return all lucky numbers in the
// matrix in any order.
// A lucky number is an element of the matrix such that it is the minimum element
// in its row and maximum in its column.
// Example 1:
// Input: matrix = [[3,7,8],[9,11,13],[15,16,17]]
// Output: [15]
// Explanation: 15 is the only lucky number since it is the minimum in its row
// and the maximum in its column
// Example 2:
// Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]]
// Output: [12]
// Explanation: 12 is the only lucky number since it is the minimum in its row
// and the maximum in its column.
// Example 3:
// Input: matrix = [[7,8],[1,2]]
// Output: [7]
// Constraints:
// m == mat.length
// n == mat[i].length
// 1 <= n, m <= 50
// 1 <= matrix[i][j] <= 10^5.
// All elements in the matrix are distinct.
/**
* @param {number[][]} matrix
* @return {number[]}
*/
const luckyNumbers = function(matrix) {
const res = [], n = matrix.length, m = matrix[0].length
for (let i = 0; i < n; i++) {
let col = 0
for (let j = 0; j < m; j++) {
if (matrix[i][j] < matrix[i][col]) col = j
}
let isMax = true
for (let k = 0; k < n; k++) {
if (matrix[k][col] > matrix[i][col]) isMax = false
}
if (isMax) res.push(matrix[i][col])
}
return res
}
;[
[[3,7,8],[9,11,13],[15,16,17]],
[[1,10,4,2],[9,3,8,7],[15,16,17,12]],
[[7,8],[1,2]],
].forEach((matrix) => {
console.log(luckyNumbers(matrix))
})
// Solution:
// 先找到每行中的最小值,再看看是否为其所在列的最大值
// Submission Result: Accepted