rozwiązania #2
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rozwiązania #2
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Ami777
reviewed
Jan 30, 2018
| //Twój kod | ||
| // nie ma informacji o danych wejściowych | ||
| const textArray = { |
| } | ||
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| for (let i = 0, len = Object.keys(textArray).length; i < len; i++) { |
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Mała podpowiedź: .forEach lub for..in wyglądają znacznie przejrzyściej.
| //Twój kod | ||
| const [ num1, num2 ] = process.argv.slice(2,4); |
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Fajne wykorzystanie destrukturyzacji tablicy :)
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