Fix dialplan expression formatting #128
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Xiretza
commented
Feb 27, 2025
| * `expr1 ? expr2 :: expr3` | ||
| Traditional Conditional operator. If `expr1` is a number that evaluates to 0 (false), `expr3` is result of the this expression evaluation. Otherwise, `expr2` is the result. If `expr1` is a string, and evaluates to an empty string, or the two characters `""`, then `expr3` is the result. Otherwise, `expr2` is the result. In Asterisk, all 3 exprs will be "evaluated"; if `expr1` is "true", `expr2` will be the result of the "evaluation" of this expression. `expr3` will be the result otherwise. This operator has the lowest precedence. | ||
| * `expr1 ~~ expr2` | ||
| Concatenation operator. The two exprs are evaluated and turned into strings, stripped of surrounding double quotes, and are turned into a single string with no invtervening spaces. This operator is new to trunk after 1.6.0; it is not needed in existing `extensions.conf` code. Because of the way asterisk evaluates `$[ ]` constructs (recursively, bottom-up), no ` ` is ever present when the contents of a `[]` is evaluated. Thus, tokens are usually already merged at evaluation time. But, in AEL, various exprs are evaluated raw, and `[]` are gathered and treated as tokens. And in AEL, no two tokens can sit side by side without an intervening operator. So, in AEL, concatenation must be explicitly specified in expressions. This new operator will play well into future plans, where expressions (`$[ ]` constructs) are merged into a single grammar. |
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I'm not sure about this whole paragraph. A bunch of stuff got chewed up during some import process, I tried to reconstruct it as best as I understood, but it still doesn't really make total sense to me.
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