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Improve error messages when typeToCode throws an exception #1450

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Improve error messages when typeToCode throws an exception #1450

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2802de3
Improve error messages when typeToCode throws an exception
fromkeith Oct 11, 2024
fea837d
Improve catch to be more specific
fromkeith Oct 18, 2024
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6 changes: 5 additions & 1 deletion json_serializable/lib/src/helper_core.dart
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Original file line number Diff line number Diff line change
Expand Up @@ -75,7 +75,11 @@ $converterOrKeyInstructions
* Set `JsonSerializable.genericArgumentFactories` to `true`
https://pub.dev/documentation/json_annotation/latest/json_annotation/JsonSerializable/genericArgumentFactories.html''';
} else if (field.type != error.type) {
message = '$message because of type `${typeToCode(error.type)}`';
try {
message = '$message because of type `${typeToCode(error.type)}`';
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We should avoid doing a catch without details. What type is thrown? Unimplemented? From which type?

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Yea, specifically this line is throwing the error

package:json_serializable/src/utils.dart 221:3

throw UnimplementedError('(${type.runtimeType}) $type');

For me type.runtimeType is equal to InvalidTypeImpl when printed in the error.

Would you prefer a refactor like this:

try {
      message = '$message because of type `${typeToCode(error.type)}`';
} on UnimplementedError catch (ex) {
     message = '$message because type is Unimplemented ($ex)';
}

} on UnimplementedError catch (ex) {
message = '$message because type is Unimplemented ($ex)';
}
} else {
final element = error.type.element?.name;
todo = '''
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