Group by - solution to example 3 changed #15
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Changed lines 428 and 429 left table changed from 'album' to 'artist' and afterwards join on 'album' this way we have all the artists, even those that don't have any album (as per the exercise stated: " Find a list of *all* artists and how many albums they have" otherwise in the proposed solution we only have the artist we have at least 1 album.
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Changed the left table to: artist and afterwards joining on table: album
this way we get all the artists, even those who have 0 albums, since instructions stated: "Find a list of all artists and how many albums they have"
Otherwise we only get the artists who have at least 1 album.