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transform(kpca) returns error #96
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How do I get the embedded coordinates of my original data points then? |
As you wrote above: original = randn(3, 100)
model = fit(KernelPCA, original)
embedded = transform(model, original) |
that is quite inefficient, because transform(kpca::KernelPCA) = sqrt.(kpca.λ) .* kpca.α' |
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Jun 4, 2019
You are right, I completely disregarded that. Fix is coming. |
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