fixed #227

ch10/ex10_05.cpp

@@ -6,19 +6,11 @@
 //  Copyright (c) 2014 pezy. All rights reserved.
 //
 //  @Brief  In the call to equal on rosters, what would happen if both rosters held C-style strings, rather than library strings? 
-//  @Answer It's the same as `std::string`
+//  @Answer For such case, std::equal is going to compare the address value rather than the string value. 
+//          So the result is not the same as std::string. Try to avoid coding this way.
+//          Check #227 for more detail.
+//  
 
-#include <algorithm>
 #include <iostream>
-#include <vector>
-#include <list>
+int main(){}
 
-int main()
-{
-    std::vector<const char *> roster1{"Mooophy", "pezy", "Queequeg"};
-    std::list<const char *>  roster2{"Mooophy", "pezy", "Queequeg", "shbling", "evan617"};
-    std::cout << std::equal(roster1.cbegin(), roster1.cend(), roster2.cbegin());
-}
-
-// out
-// 1