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Added some symmetric gp stuff (incomplete) and changes re: disc 2day
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Elaborated on how \C G is a G \times G module and added a missing \tr
to explanation of Mackey to D_8.
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ghseeli committed Dec 8, 2017
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162 changes: 152 additions & 10 deletions Class Notes/Algebra/representation-theory-of-finite-groups.tex
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\usepackage{tikz}
\usetikzlibrary{cd}
\usepackage{bbm}
\usepackage{ytableau}
\usepackage{todonotes}

\usepackage{../notes}
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\newcommand{\Res}{\operatorname{Res}}
\newcommand{\Ind}{\operatorname{Ind}}
\newcommand{\bs}{\textbackslash}
\newcommand{\partitionof}{\vdash}
\newcommand{\T}{\mathsf{T}}

\numberwithin{thm}{section}

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& = \tr_{\Hom_\C(W,V)}\left(\frac{1}{|G|}\sum_{g \in G} g\right)
\end{align*}
However, \(P := \frac{1}{|G|} \sum_{g \in G} g\) is a homomorphism of
\(G\) representations and the image of \(P\) is
stable under any action of \(G\). Thus, for arbitrary representation
\(G\) representations (that is, \(P.v\) is a representation
of \(G\)) and the image of \(P\) is
stable under any action of \(G\) since \(g.Pv = Pv\). However, the only
such irreducible representation is the trivial representation or the
zero representation. Thus, for
arbitrary representation
\(U\), \(\tr_U(P)\) simply counts
the number of times the trivial representation occurs as a
subrepresentation of \(U\). However, considering \(\Hom_\C(W,V)\) as
Expand Down Expand Up @@ -1098,6 +1105,18 @@ \section{The Regular Representation Revisited}
each class function of \(G_1 \times G_2\) which is orthogonal to
characters of the form \(\chi_1 \cdot \chi_2\) is zero.
\end{rmk}
\begin{prop}
One can realize \(\C[G]\) as a \(G \times G\)-module via the
action \[
(h,k).g = hgk^{-1}
\]
extended linearly.
\end{prop}
\begin{proof}
Indeed, \[
(h',k').(h,k).g = (h',k').hgk^{-1} = h'hgk^{-1}k'^{-1} = (h'h,k'k).g
\]
\end{proof}
\begin{thm}
The regular representation decomposes as a direct sum of \(G \times
G\) representations. More specifically, \[
Expand Down Expand Up @@ -1650,14 +1669,15 @@ \section{Mackey Theory}
\end{array}
\]
If \(\rho^i\) is the irreducible representation of \(\Z_4\)
corresponding to \(\chi_i\), then we notice that \(\rho^2_s(r) =
\rho^2(srs) = \rho^2(r^{-1}) = \rho^2(r)\), so \(\Ind_{\Z_4}^{D_8}
\rho^2\) will \emph{not} be irreducible. On the other hand, one can
check \(\rho^1_s(r) = \rho^1(srs) = \rho^1(r^{-1}) = \rho^3(r)\), so
\(\rho^1_s\) and \(\rho^1\) are orthogonal, thus sharing no
irreducibles. Thus, it must be that \(\Ind_{\Z_4}^{D_8} \rho^1\) is
irreducible. In fact, one can check \(\Ind_{\Z_4}^{D_8} \rho^1 =
\Ind_{\Z_4}^{D_8} \rho^3\) will give the only irreducible
corresponding to \(\chi_i\), then we notice that \(\tr \rho^3_s(r) =
\tr \rho^3(srs) = \tr \rho^3(r^{-1}) = -1 = \tr \rho^3(r)\), so
\(\Ind_{\Z_4}^{D_8}
\rho^3\) will \emph{not} be irreducible. On the other hand, one can
check \(\rho^2_s(r) = \rho^2(srs) = \rho^2(r^{-1}) = -i = \rho^4(r)\), so
\(\rho^2_s\) and \(\rho^2\) are orthogonal, thus sharing no
irreducibles. Thus, it must be that \(\Ind_{\Z_4}^{D_8} \rho^2\) is
irreducible. In fact, one can check \(\Ind_{\Z_4}^{D_8} \rho^2 =
\Ind_{\Z_4}^{D_8} \rho^4\) will give the only irreducible
\(2\)-dimensional representation of \(D_8\).
\end{example}
\section{Representations of Nilpotent Groups}
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\(p\)-elementary subgroups of \(G\). Then, \([R(G):V_p] < \infty\)
and \(\gcd([R(G):V_p],p) = 1\).
\end{thm}
\todo{Actually prove Brauer's theorem.}
\section{Example: Representations of the Symmetric Group}
Elements of the symmetric group \(\Sym_n\) can be represented in
\(1\)-line notation as products of disjoint cycles, and to each
element, we can assign a \de{cycle type} in the form of a partition of
\(n\).
\begin{example}
Consider \((12345)(876)(9,10) \in \Sym_{10}\). This cycle has cycle
type \((5,3,2) \partitionof 10\).
\end{example}
Partitions are useful combinatorial tools with many applications
beyond what is described here. We can also define a partial order on
tableau.
\begin{defn}
Given partitions \(\lambda = (\lambda_1, \lambda_2,
\ldots) \partitionof n\) and \(\mu = (\mu_1, \mu_2, \ldots)\), we
say that \(\lambda \leq \mu\) if \[
\begin{cases}
\lambda_1 \leq \mu_1 \\
\lambda_1 + \lambda_2 \leq \mu_1 + \mu_2 \\
\vdots\\
\lambda_1 + \cdots + \lambda_k \leq \mu_1 + \cdots + \mu_k \\
\vdots
\end{cases}
\]
\end{defn}
\begin{example}
Using the notation that \((2^2,1^2) = (2,2,1,1)\), the following
partial order is induced on the partitions of \(6\).
\[ \begin{tikzcd}[row sep=tiny, column sep=tiny]
& (6) \ar[d] & \\
& (5,1) \ar[d] & \\
& (4,2) \ar[ld] \ar[rd] & \\
(3,3) \ar[rd] & & (4,1^2) \ar[ld] \\
& (3,2,1) \ar[ld] \ar[rd] & \\
(3,1^3) \ar[rd]& & (2^3) \ar[ld] \\
& (2^2, 1^2) \ar[d] & \\
& (2,1^4) \ar[d] & \\
& (1^6) &
\end{tikzcd}
\]
\end{example}


It is also useful to realize partitions of \(n\) as Young
diagrams. Once again, we shall define the correspondance via an
example.
\begin{example}
We can represent a partition \((\lambda_1, \lambda_2, \ldots)\) as a
\de{Young diagram} with \(\lambda_i\) boxes on the \(i\)th row. So,
consider \((5,3,2) \partitionof 10\). The corresponding diagram
would be \[
\ydiagram{5,3,2}
\]
Furthermore, we can fill in the boxes of the diagram to get a \de{Young
tableau}. For example \[
\begin{ytableau}
1 & 2 & 3 & 4 & 5 \\
6 & 7 & 8 \\
9 & 10
\end{ytableau}
\]
Furthermore, \(\Sym_n\) can act on a Young tableau by permuting the
numbers. So, \((12345)(876)(9,10) \in \Sym_10\) would act on the
above diagram to yield \[
\begin{ytableau}
2 & 3 & 4 & 5 & 1\\
8 & 6 & 7 \\
10 & 9
\end{ytableau}
\]
\end{example}
Now, using this combinatorial device, we can define the following.
\begin{defn}
Let \(\T\) be a tableau of shape \(\lambda \partitionof n\) for \(n
\in \N\). Then, we define the \de{row stabalizer subgroup}
\(R(\T) \subgroup \Sym_n\) to be the subgroup of
permutations such that
every permutation in \(R(\T)\) preserves the elements in
the rows of \(\T\). One analogously defines \(C(\T)\) to be the
\de{column stabalizer subgroup}.
\end{defn}
\begin{example}
In the example above, \((12345)(876)(9,10)\) is in the row
stabalizer of the tableau. In fact, in that setup \(R(\T) \isom \Sym_5 \times
\Sym_3 \times \Sym_2\).
\end{example}
Now, given \(\Sym_n\), we automatically know of \(2\) irreducible,
\(1\)-dimensional, complex representations, namely the trivial
representation
and the sign/alternating representation. Furthermore, we know that
conjugacy classes of \(\Sym_n\) are encoded by cycle type, which are
encoded by partitions of \(n\). So, since character tables are square,
there must be as many irreducible representations of \(\Sym_n\) as
there are partitions of \(n\). Thus, we have \[
\{\text{Partitions of }n\} \onetoonecorrespondance
\{\text{Irreducible representations of }\Sym_n\}
\]
Our task, then, is to figure out what these irreducible
representations are. A systematic treatment will not be given here,
but some of the tools in the previous chapters will be used to get an
idea of some results about the representation theory of symmetric
groups. For more, see \cite{james}, \cite{fulton}.
\begin{defn}
We define the \de{row symmetrizer} of a tableau \(\T\) of shape
\(\lambda\) to be \[
P(\T) := \sum_{\alpha \in R(\T)} \alpha
\]
and the \de{column symmetrizer} to be \[
Q(\T) := \sum_{\alpha \in C(\T)} \sgn(\alpha) \alpha
\]
\end{defn}

\begin{bibdiv}
\begin{biblist}
Expand Down Expand Up @@ -1884,12 +2016,22 @@ \section{Brauer's Theorem}
year={2011}
note={\url{http://math.mit.edu/~etingof/replect.pdf}}
}
\bib{fulton}{book}{
author={Fulton, Wiliam}
title={Young Tableaux}
year={1997}
}
\bib{princeton-companion}{article}{
author={Gronjnowski, Ian}
title={Representation Theory}
journal={The Princeton Companion to Mathematics}
pages={419--431}
}
\bib{james}{book}{
author={James, G. D.}
title={The Representation Theory of the Symmetric Groups}
year={1978}
}
\bib{aw}{article}{
author={Seelinger, George H.}
title={Artin-Wedderburn Theory}
Expand Down

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