Fix like to be used as condition to generate valid sql

[registrs]

Fixes #issue_number

Problem

Currently when using "like" there's an error: Incorrect syntax near the keyword 'like'
It generates: "...WHERE 1 = name like %?..." which causes the error on sql syntax (MSSQL)

Solution

Changed boolean to asConditon to make comparison with correct types, so sql would be valid

Checklist

• Unit test all changes
• Update README.md if applicable
• Add [WIP] to the pull request title if it's work in progress
• Squash commits that aren't meaningful changes
• Run sbt scalariformFormat test:scalariformFormat to make sure that the source files are formatted

@getquill/maintainers

[guersam]

Having the same issue on SQL Server.

[guersam]

Just opened #2297 including this change, but I'll happily rebase if this one gets merged first.

[CLAassistant]

All committers have signed the CLA.

[deusaquilus]

@registrs This looks right, thanks! Could you please add a test for this case in SqlDslSpec.scala, i.e. just verify the produced SQL string. Then I'll merge.

[registrs]

@registrs This looks right, thanks! Could you please add a test for this case in SqlDslSpec.scala, i.e. just verify the produced SQL string. Then I'll merge.

Hi, sorry but there's issue that I don't know how to add more commits for this pull request as this is very old commit and since then project stucture has changed - this commit has:

This commit does not belong to any branch on this repository.

So simplest way I guess would be to address adding test in separate pull request.