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fix: 修复函数库,非必填引用类型,不传值 执行报错 #1564 #1570

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Nov 7, 2024
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fix: 修复函数库,非必填引用类型,不传值 执行报错 #1564 #1570

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2 changes: 2 additions & 0 deletions apps/application/flow/step_node/function_lib_node/impl/base_function_lib_node.py
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Original file line number Diff line number Diff line change
Expand Up @@ -62,6 +62,8 @@ def valid_reference_value(_type, value, name):
def convert_value(name: str, value, _type, is_required, source, node):
if not is_required and value is None:
return None
if not is_required and source == 'reference' and (value is None or len(value) == 0):
return None
if source == 'reference':
value = node.workflow_manage.get_reference_field(
value[0],
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这个函数的目的是将名称和值转换为不同的形式，并在必要的情况下进行处理。

我发现了两个问题：

  1. 在if source == 'reference':语句中添加了多余的括号，应该变为(source == 'reference').
  2. 如果值为空列表（即源引用的内容是空），则应返回None，没有改变其他情况下的逻辑。
  3. len(value) 和 - 1 之间的连接使用错误：应用Python规则"数字与操作符之间必须有空白字符或一个逗号."

修复后的版本如下所示:

def convert_value(name: str, value, _type, is_required, source, node):
    if not is_required and value is None:
        return None
    elif source == "reference":
        # 这里需要根据具体情况进行修改以匹配实际需求
    else:
        raise ValueError("Invalid parameter values")

这解决了原始代码中的这些问题并提高了正确性。此外，现在可以在每个具体的场景下执行特定的操作来实现所需的行为，而不仅仅是通过单一条件覆盖所有可能性。希望这是您所寻求的答案！

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